pass4sure microsoft MB6-527 v2.83

GP 10.0 Installation & Configuration : MB6-527 Exam
Product DescriptionExam Number/Code: MB6-527
Exam Name: GP 10.0 Installation & Configuration

“GP 10.0 Installation & Configuration”, also known as MB6-527 exam, is a Microsoft certification. With the complete collection of questions and answers, Pass4sure has assembled to take you through 60 Q&As to your MB6-527 Exam preparation. In the MB6-527 exam resources, you will cover every field and category in Microsoft Business Solutions helping to ready you for your successful Microsoft Certification
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GP 10.0 Installation & Configuration
Exam Number: MB6-527 Exam
Associated Certifications: GP 10.0 Installation & Configuration
Duration: 60 Q&As
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Like actual certification exams our product is in multiple-choice questions (MCQs).

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QUESTION 1:
You are the network administrator for Certkiller .
You are installing Windows 2000 Server on a new computer by using the Windows
2000 Server compact disk. The computer has five 18-GB hard disks Dick0, Disk1,
Disk2, Disk3, and Disk4. The disks do not have any partitions defined.
You want to use as much space on Disk0 as possible for the partition on which
Windows 2000 Server is installed. You want the disk on which you install Windows
2000 Server to be fault tolerant. You also want as much disk space as possible across
the other disks to be available for data storage and to be fault tolerant.
What should you do? (Each correct answer presents part of the solution. Choose
three)
A. Install Windows 2000 Server on a 4-GB NTFS partition on Disk 0. Configure the five
disks as dynamic disks.
B. Install Windows 2000 Server on a 18-GB NTFS partition on Disk 0. Configure the
five disks as dynamic disks.
C. Create a RAID-5 volume using Disk2, Disk3, and Disk4.
D. Create a stripped volume using Disk2, Disk3, and Disk4.
E. Create a RAID-5 volume using all disks.
F. Create a stripped volume using all disks.
G. Select the volume on Disk0 and add a mirror using Disk1.
Answer: B, C, G
Explanation: RAID-5 volume is where data is written to 3 to 32 physical disks at the
same rate, and is interlaced with parity to provide fault tolerance for a single disk failure.
Good read performance; good utilization of disk capacity; expensive in terms of
processor utilization and write performance as parity must be calculated during write
operations.
Only Windows 2000 supports dynamic storage. To support dynamic storage, a single
partition is created that includes the entire disk. A disk that you initialize for dynamic
storage is a dynamic disk. Dynamic disks are divided into volumes, which can consist of
a portion or portions of one or more physical disks. A dynamic disk can contain simple
volumes, spanned volumes, striped volumes (RAID-0), mirrored volumes (RAID-1), and
striped with parity volumes (RAID-5). You create a dynamic disk by upgrading a basic
disk.
A Mirrored volume is where two disks contain identical copies of data. The only
software RAID supported on the system volume. Good read and write performance;
excellent fault tolerance; but costly in terms of disk utilization, because 50 percent of the
volume’s potential capacity is used for data redundancy.
Incorrect answers:
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A: It is not necessary to install Windows 2000 Server on a 4-GB NTFS partition on
Disk0. Disk0 consists of 18-GB.
D: Striped volume is where data is written to 2 to 32 physical disks at the same rate. It
offers maximum performance and capacity but no fault tolerance.
E: The main disadvantage of a RAID-5 volume is that once a drive fails, system
performance suffers until you rebuild the RAID-5 volume. This is because the parity
information must be recalculated through memory to reconstruct the missing drive. If
more than one drive fails, the RAID-5 volume becomes inaccessible. This does not bode
well for fault tolerance as is required in this question.
F: Striped volumes do not provide fault tolerance.
Reference:
Microsoft Corporation, Self-Paced MCSE Training Kit: Microsoft Windows 2000 Server,
Microsoft Press, Redmond, 2000, Chapter 4, Lesson 1
QUESTION 2:
You are the network administrator for Certkiller .
Your Windows 2000 Server computer named Certkiller 1 contains two 36-GB hard
disks. Disk 0 and Disk 1. Each disk is configured as a basic disc and has a single
36-GB NTFS partition. Both partitions are backed up to a tape each night. The
partition on Disk 1 stores user data. Most users at Certkiller encrypt their files. Disk
1 fails. You replace it with a new hard disk and create a single NTFS partition.
You need to recover the data as quickly as possible while maintaining the security of
the files on Disk 1.
What should you do?
A. Restore the contents of Disk 1 from the most recent tape backup to a second file
server. Instruct users to copy their files from the second file server to the new partition.
B. Restore the contents of Disk 1 from the most recent tape backup to a second file
server. Log on to Certkiller 1 console as a recovery agent. Copy the files from the second
file server to the new partition.
C. Restore the contents of Disk 1 from the most recent tape backup to the new partition
on Certkiller 1. Instruct the users to verify the integrity of their files.
D. Restore the contents of Disk 1 from the most recent tape backup to the new partition
on Certkiller 1. Run the cipher command to decrypt the files.
Answer: C
Explanation: Verify Data After Backup is used to confirm that files are correctly backed
up. Windows Backup compares the backup data and the source data to verify that they
are the same. Microsoft recommends that you select this option. Restoring the contents of
Disk 1 from the most recent backup tape to the new partition on Certkiller 1 and
instructing the users to verify the integrity of their files would accomplish the task at
hand the quickest and still maintain the security of the files of Disk 1.
Incorrect answers:
A: There is no need to make use of a second file server. This will not accomplish the task
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as quick as possible. Besides, this does not mean that the security on the files will be kept
in tact.
B: There is no need to make use of a second file server, neither as a recovery agent and
then copying files from the second file server to the new partition. This will take too long
in this case.
D: The first part of this option is correct; but the cipher command is used to decrypt files.
Reference:
Microsoft Corporation, Self-Paced MCSE Training Kit: Microsoft Windows 2000 Server,
Microsoft Press, Redmond, 2000, Chapter 4, Lesson 2
QUESTION 3:
Exhibit:
You are the network administrator of a Windows 2000 workgroup.
The network is part of a small office that is configured as shown in the Network
diagram. There is no DHCP server on the network. All Windows 2000 Professional
client computers use APIPA addresses. Certkiller B is configured to have static IP
address. However, no applications on Certkiller B require a static IP address.
Certkiller A uses dial-up connection to connect to the Internet. After you enable
Internet Connection Sharing on Certkiller A you discover the Certkiller B cannot
access the Internet.
You want to ensure that all network computers can connect to Certkiller A and access
the Internet.
What should you do?
A. On all of the computers, configure static IP addresses in the range of 192.168.0.2 to
192.168.255.255.
B. On Certkiller B, configure static IP addresses in the range of 192.168.0.2 to
192.168.255.255.
C. Configure Certkiller A with a static IP address of 169.254.53.98.
D. Configure Certkiller B to obtain its IP address automatically.
E. Configure Certkiller A to obtain its IP address automatically.
F. On all of the computers, configure a subnet mask of 255.255.255.0
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Answer: D
Explanation: When you enable Internet Connection Sharing, the server with the
shared connection becomes a DHCP server giving out IP addresses in the
192.168.0.0/24 range. In this question, all the DHCP enable computers now have a
192.168.0.x IP address, except Certkiller B which has a static IP address. The solution
to the question is to configure Certkiller B to obtain its IP address automatically.
Certkiller B will then receive a 192.168.0.x IP address from the ICS computer.
Incorrect Answers:
A: The problem is with Certkiller B not the client computers. Therefore, we do not need
to change anything on the client computers.
B: This solution could lead to duplicate IP addresses in use on the network.
C: There is no problem with Certkiller A so we don’t need to change anything on
Certkiller A.
E: There is no problem with Certkiller A so we don’t need to change anything on
Certkiller A.
F: The problem is with Certkiller B not the client computers. Therefore, we do not need to
change anything on the client computers.

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